During a baseball game, a batter hits a pop-up to a fielder 93 m away. The acceleration of gravity is 9.8 m/s2.If the ball remains in the air for 5.4 s, howhigh does it rise?Answer in units of m

Explanation:

It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m

The ball remains in the air for 5.4 s, the time of flight is 5.4 s

Time of flight :

Maximum height of the projectile :

We need to find H.

So,

So, it will rise to a height of 35.72 m.