If two such generic humans each carried 2.0 C coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650 N weight?

Given :

Charge on human 1 , .

Charge on human 2 , .

Force of attraction between them , F = 650 N .

To Find :

Force between them , F =- 650 N .( force between opposite charge is -ve )

Solution :

We know , electrostatics force between two charge is given by :

Here k is universal gravitational constant , .

Putting all given value in above equation we get :

Hence , this is the required solution .

c. newton's third law of motion