An airplane lands on the runway at a velocity of 22.7m/s. The plane accelerates at a rate of -3.3m/s2 until it comes to rest. How much time does it take the plane to stop? (round to the nearest tenth).

time = 6.9 s

Explanation:

velocity of the plane v = 22.7 m/s

acceleration of the train a = -3.3 m/s^2

it finally comes to res, final velocity u = 0 m/s

time t = ?

using the equation

v = u + at

substituting, we have

0 = 22.7  + (-3.3)t

0 = 22.7 - 3.3t

3.3t = 22.7

t = 22.7/3.3 = 6.9 s

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form