A car travelling 10m/s increases its speed to 20m/s over a time of 4s. What is the acceleration of the car? A car is traveling at a speed of 15m/s. It experiences an acceleration of -3m/s^2, that lasts for 4 seconds. What is the final velocity of the car? I need an expanation on HOW to solve this.

Explanation:

Acceleration is the change in velocity with respect to time.

Acceleration = change in velocity/Time

Acceleration = final velocity - initial velocity/Time

Given initial velocity = 10m/s

Final velocity = 20m/s

Time taken = 4s

Acceleration = 20-10/4

Acceleration = 10/4

Acceleration =2.5m/s²

For the second part of the question:

Given parameters

initial velocity = 15m/s

acceleration = -3m/s²

time = 4seconds

a = v-u/t

-3 = v-15/4

cross multiply

-12 = v-15

add 15 from both sides

-12+15 = v-15+15

3 = v

Hence the final velocity of the car is 3m/s

a person with a mass of 106kg has a weight of 1060n

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.