A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction parallel to the railway track with a speed of 5 ms–1. The time taken by the parrot to cross the train is equal to.?

The time taken by the parrot to cross the train is = 10 m/s

Explanation:

given:

A train of 150 m length is going toward north direction at a speed of 10 m/s

and a parrot is flying towards south direction parallel to the railway track with a speed of 5 m/s

find;

The time taken by the parrot to cross the train

using the distance over speed relation formula t = d / v

where:

v = velocity

d = distance

t = time

v = 10 m/s + 5 m/s = 15 m/s (combine velocity)

d = 150 m

t = ?

plugin values into the formula

t =   150  

         15

t = 10 m/s

therefore,

The time taken by the parrot to cross the train is = 10 m/s

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s