How far does a freely falling apple drop in 5.6 s after being released from rest?

The freely falling apple will drop 153.67 m in 5.6 secs when released from rest

For An apple at rest :

Initial velocity ( u ) = 0 m/s

free fall acceleration ( due to gravity ) (g) = 9.8 m/s²

Time travelled by apple ( t )  = 5.6 s

To determine the how far the apple will travel after been released

we will apply this formula

S = 0 ( 5.6 ) + 1/2 * ( 9.8 ) * ( 5.6 )²

   = 153.67 m

Hence we can conclude that the freely falling apple will drop 153.67 m when released from rest.

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Calculate the height covered by a freely falling apple drop in 5.6 seconds.

According to the Second equation for free falling body

change tension

its c i just checked it