The man pulls on the cord with a force of 350N. Represent this force acting on the support A, as a Cartesian vector and determine its direction

hi liqus here is ur ans;

Explanation:

End points of the cord are A(0m,0m,7.5m)and

B(3m,-2m,1.5 m)

r=(3m-0m)i + (-2m-0m)j + (1.5m-7.5m)k

=(3i-2j-6k)m

Magnitude=length of cord AB

r=(3m)2 +(-2m)2 +(-6m)2 = 7m

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