Two charged spheres on a frictionless horizontal surface are attached to opposite ends of a string & are in static equilibrium. The 18 kg red sphere has more charge than the 11 kg green sphere. The total charge magnitude on the spheres is 10 μC & they have the same polarity. As a result the tension is 2.5 N & the centers of the spheres are 0.06 m apart. Determine the charge magnitude on each sphere.

the red sphere has a charge of 9.899 10⁻⁶ C and

the green sphere 0.101 10⁻⁶ C

Explanation:

For this exercise we will use coulomb's law

          F = k q₁ q₂ / r²

where they indicate the value of the force F = 2.5 N, the distance between them r = 0.06 m

they also indicate the value of the total load

         q₁ + q₂ = 10 10⁻⁶ C

we substitute the values

         2.5 = 9 10⁹ q₁ q₂ / 0.06²

         2.5 0.06 2/9 10⁹ = q₁ q₂

         1 10⁻¹² = q₁ q₂

         10 10⁻⁶= q₁ + q₂

we have two equations with two i unknowns, so the system can be solved.

         q₁ = 1 10⁻¹² / q₂

we substitute in the other equation

         10 10⁻⁶ = 10⁻¹² / q₂ + q₂

let's solve the equation

         10 10⁻⁶ q₂ = 10⁻¹² + q₂²

         q₂² - 10⁻⁵ q₂ + 10⁻¹² = 0

          q₂ = [10⁻⁵ ± √(10⁻¹⁰ - 4 10⁻¹²)] / 2

          q₂ = [10⁻⁵ + - 0.9798 10⁻⁵] / 2 = 10⁻⁵ (1 + - 0.9798) / 2

          q₂ = 0.9899 10⁻⁵ C

          q₂ = 0.0101 10⁻⁵ C

let's find the charge of the other sphere

         q₂ = 0.9899 10⁻⁵ C

         q₁ = 10⁻⁵ - q₂

          q₁ = 10⁻⁵ - 0.9899 10⁻⁵

          q₁ = 0.0101   10⁻⁵    C

therefore the red sphere has a charge of 9.899 10⁻⁶ C and

the green sphere 0.101 10⁻⁶ C

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this