A cannon is fired horizontally from the edge of a 100 meter tall cliff. The muzzle velocity of the cannon is 180 m/s . How far from the base of the cliff does the hall land? A-.55m
B-813.16m
C-3673.47
D-700m

B - 813.16 m

Explanation:

First, find the time it takes to land.  Given in the y direction:

Δy = 100 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

100 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 4.52 s

Now find the distance traveled in that time.  Given in the x direction:

v₀ = 180 m/s

a = 0 m/s²

t = 4.52 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (180 m/s) (4.52 s) + ½ (0 m/s²) (4.52 s)²

Δx = 813.16 m

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