Carlos runs with velocity \vec{v}v →= (5.6 m/s, 29o north of east) for 10 minutes. How far to the north of his starting position does Carlos end up? (Give your answer to the nearest meter)

1629 metres

Explanation:

Given that Carlos runs with velocity v = (5.6 m/s, 29o north of east) for 10 minutes.

To the north, the velocity will be:

V = 5.6 × sin 29

V = 2.715 m/s

Convert the time to second

Time = 10 × 60 = 600

Using the formula below

Velocity = distance/ time

Substitute all the parameters into the formula

2.715 = distance/600

Distance = 2.715 × 600

distance = 1629 m

490 n

f=125n a=2.5m/s2