find the minimum diameter of steel which is used to raise a load of 4000n if the rod is not to exceed 95 mn/m^2

The minimum diameter of steel is 7.32 mm

Explanation:

Given;

load raised by the steel, F = 4000 N

steel rating (tensile stress), σ = 95 MN/m² = 95 N/mm²

Area of the steel is given by;

Thus, the minimum diameter of the steel = 2r

D = 2(3.66 mm)

D = 7.32 mm

Therefore, the minimum diameter of steel is 7.32 mm

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human population grows worldwide

the moving of the box is a result of centripetal force. think of that  as a car or a truck in this case creates a turn, the force of friction performing upon the turned wheels of the car runs centripetal force obligatory for circular motion for the things inside it.