What is the average acceleration of the object between t=2 s and t=6 s?

Explanation:

Acceleration is the change in velocity of a body with respect to time.

a = Δv/Δt

a = v-u/t₂-t₁

v is the final velocity

u is the initial velocity

t₂ is the final time

t₁ is the initial time

To calculate the average acceleration of the object between t=2 s and t=6 s, we will get the equivalent velocity of the body during this times from the graph shown in the attachment.

At t₁ = 2s, u = 3m/s

at t₂ = 6s, v = 5m/s

Substitute the given parameters into the formula for calculating acceleration;

Hence the average acceleration of the object between t=2 s and t=6 s is 0.5m/s²

the answer is kevlar

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