A tennis ball with a speed of 13.2 m/s is moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 10.362 m/s.
If the ball is in contact with the wall for
0.0141 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take "toward the wall” to be the positive
direction.
Answer in units of m/s
Hata che war
12

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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From my calculation, i got 3.655moles