Two steamrollers begin 100 m apart and head toward each other, each at a constant speed of 1.00 m/s . At the same instant, a fly that travels at a constant speed of 2.40 m/s starts from the front roller of the southbound steamroller and flies to the front roller of the northbound one, then turns around and flies to the front roller of the southbound once again, and continues in this way until it is crushed between the steamrollers in a collision. What distance does the fly travel?

The fly travels 2.4 m

Explanation:

Since the Two steamrollers begin 100 m apart and head toward each other, each at a constant speed of 1.00 m/s, we can find the time until they crash by the formula:

Distance = Speed × Time

Time = Distance /Speed

Time = (100 m) / (1 m/s)

Time = 100 hours

Now, the fly will spend the same amount of time traveling as the steamrollers.

Since the fly moves at a speed of 2.4 m/s and we have a time of one hour the steamroller take to collide, then the fly will go a distance of;

Distance = speed x time = 2.4 × 1 = 2.4 m

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

it is a negative acceleration