A dog runs 5m north, then 3m south ,then 20 m east, then 6m west then 2m north, then 4m north, then 6m east, 10m south, then 2m west, then 4m north
a. What distance did the dog travel?
b. What is his displacement from his starting place?

lexy is right because she has the labeled s

where is the photo and the answer choices?

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .