A biker with an initial velocity of 16.0 m/s slows uniformly to 6.0 m/s in 8.0 seconds. What is the acceleration of the car during this 8.0-second interval?

-1.25 m/s²

Explanation:

Given:

v₀ = 16.0 m/s

v = 6.0 m/s

t = 8.0 s

Find: a

v = at + v₀

6.0 m/s = a (8.0 s) + 16.0 m/s

a = -1.25 m/s²

e) none of the above answers are correct

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day