A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction for 3600.0 seconds. Hint: Draw a position- time graph. a. Where is the runner at time t= 5.0 s?
b. Where is the runner at time t= 15.0 s?

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So,

From equation (i)

As the jogger starts from origin, so, the distance, , also represents the position of the jogger at the time s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

So, the jogger is at a distance of 75 m from the origin.

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

where’s the list ? the question is incomplete