Not sure what i’m doing how do i do this??

Explanation:

Given:

v₀ = 25 m/s

v = 0 m/s

a = -9.8 m/s²

1a) Find t.

v = at + v₀

0 m/s = (-9.8 m/s²) t + 25 m/s

t = 2.55 s

1b) Find Δy.

v² = v₀² + 2aΔy

(0 m/s)² = (25 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 31.9 m

dicrrdirrkdirckrrdrrk ; jhgfdsgrthyjkul; i'lkjhgfdskhjl; jhgdfs

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west