Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h flies off the front of one train when they are 66 km apart and heads directly for the other train. On reaching the other train it flies directly back to the first train, and so forth. (We have no idea why a bird would behave in this way.) What is the total distance the bird travels before the trains collide?

The value is

Explanation:

From the question we are told that

The speed of each train is

The speed of the bird is

The distance between the trains is

Generally the time taken before the collision occurs is mathematically represented as

=>

=>

The total distance covered by the bird is mathematically represented as

=>  

=>  

a) are muscles that have bands.

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answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.