Suppose a force of N is required to stretch and hold a spring m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring m from its equilibrium position? c. How much work is required to stretch the spring m from its equilibrium position? d. How much additional work is required to stretch the spring m if it has already been stretched m from its equilibrium?

The question is incomplete; the complete question is;

Suppose a force of 40 N is required to stretch and hold a spring 0.2m from its equilibrium position.

a. Assuming the spring obeys Hooke's law, find the spring constant k.

b.How much work is required to compress the spring 0.1m from its equilibrium position?

c.How much work is required to stretch the spring 0.4 m from its equilibrium position?

d.How much additional work is required to stretch the spring 0.2m if it has already been stretched 0.2m from its equilibrium?

a) 200 Nm-1

b) 1 J

c) 16 J

d) 12 J

Explanation:

From;

F= Ke

Where;

K= force constant

e= extension

Hence K= F/e = 40 N/0.2 m = 200 Nm-1

b) W= 1/2 Ke^2

Since e= 0.1 m

W= 0.5 × 200 × (0.1)^2

W= 1 J

c)

W= 0.5 × 200 × (0.4)^2

W= 16 J

d)

Work in stretching by 0.2 m = W= 0.5 × 200 × (0.2)^2 = 4 J

If stretched an additional 0.2 m, we have a total of 0.4 m for which the energy is 16 J.

The additional energy now is; 16 J - 4 J = 12 J

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000