11. Block A and block B move toward each other on a level frictionless track. Block A has mass m and velocity +v. Block B has mass 2m and velocity -v. The blocks collide, and during the collision the
magnitude of the net force exerted on block A is F. What is the magnitude of the net force exerted
on block B, and why does it have that value?
a) 2F, because the mass of block B is twice that of block A and the blocks have
the same acceleration during the collision.
b) F/2, because the mass of block B is twice that of block A and the blocks have
the same acceleration during the collision.
c) F, because the blocks have the same speed immediately before the collision.
d) F, because the net force is equal to the mutual contact force between the
blocks.

The correct option is;

d) F, because the net force is equal to the mutual contact force between the blocks

Explanation:

The given information are

The mass of block A = m

The velocity of block A = +v

The mass of block B = 2·m

The velocity of block B = -v

Given that the two blocks collide, we have;

Initial total momentum = m × v + 2·m×(-v) = m·(v - 2·v) = -m·v

Final total momentum = m × v₁ + 2·m×v₂ = m·(v₁ + 2·v₂)

From the law of conservation of linear momentum, we have;

m·(v₁ + 2·v₂) = -m·v

v₁ + 2·v₂ = -v

Therefore, the resultant velocity of the two blocks is -v, and the direction of the block A is reversed and the resultant inertia is equivalent to the inertia of block A

Therefore;

The force exerted on block B = The force exerted on block A = The rate of change of momentum experienced by the two blocks = The mutual contact force experienced between the blocks.

divide the right side by the left side

0.024÷1.2=0.02 for example

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