A ball initially rolling at 10 m/s comes to a stop in 25 seconds. Assuming the ball hass uniform deceleration, how far does it travel during this time interval PLS HURRY

x = 125 [m]

Explanation:

To solve this problem we must use the following kinematics equations.

where:

Vf = final velocity = 0

Vi = initial velocity = 10 [m/s]

t  = time = 25 [s]

a = acceleration [m/s2]

Note: the negative sign of the last term of the equation means that the speed decreases, that is, the body slows down.

Now replacing:

0 = 10 - (a*25)

a = 0.4 [m/s^2]

Now we must find the displacement value with the following equation and with the acceleration value found.

where:

x = displacement [m]

(10)^2 = 2*0.4*x

x = 125 [m]

answer: option c.

explanation:

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s