Two children tug on a toy of mass 2.0kg. Costa pulls with a force of 10.0N[W 30degrees S]. The toy slides with an acceleration of 2.5m/s^2 in the direction of the net force. (North and West are positive)
A) Determine the value of the frictional force acting on the toy.
b)Determine the coeffieicent of friction.

A) 23 joules

B)8

Explanation: trust me

vi = 18.5 m/s

vf = 46.1 m/s

t = 2.47 s

Find:

d = ??

a = ??

a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2

d = 45.7 m + 34.1 m

d = 79.8 m

(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)

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