If the height of a lab table in a classroom is 0.60 m, how long would it take for a ball launched off the edge of these tables to reach the floor?

Explanation:

Using the equation of motion S = ut+1/2gt² where;

S is the height of the table = 0.60m

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.81m/s²

t is the time taken

Substitute

0.6 = 0+1/2(9.81)t²

0.6 = 4.905t²

t² = 0.6/4.905

t² = 0.1223

t = √0.1223

t = 0.3497

t≈0.35secs

Hence it will take 0.35seconds for a ball launched off the edge of these tables to reach  the floor

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.