A plane lands and comes to a complete stop through 180 m of runway with a deceleration of 6.25 m/s2 [N]. Determine the plane’s velocity when it first touched the landing strip.

47.43 m/s

Explanation:

Given that,

Final speed of a plane, v = 0

Distance, d = 180 m

Acceleration of the plane, a = -6.25 m/s² (deceleration )

We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :

So, the plane's velocity when it first touched the landing strip is 47.43 m/s.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

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