A 4.0-mF capacitor is discharged through a 4.0-kΩ resistor. How long will it take for thecapacitor to lose half its initial stored energy?

The time it will take the capacitor to loss half of its stored energy is 11.1 s.

Explanation:

Given;

capacitance, C = 4.0-mF = 0.004 F

resistance, R = 4.0-kΩ = 4000 Ω

The voltage of a capacitor at an instant time is given  by;

the final voltage, V is half of the initial voltage, V₀ at the time t

V = V₀/2

Therefore, the time it will take the capacitor to loss half of its stored energy is 11.1 s.

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