If a marker was dropped into a graduated cylinder filled with 20 mL of water, and the water level rose to 26 mL, what would the be volume of that marker?

density

=

2.9

g/cm

3

Explanation:

We're asked to find the density of the rock, given some mass and volume information.

We're given that the mass of the system before the rock was added was

120

g

. The mass after the rock was added was

250

g

, so the rock's mass is

m

rock

=

m

final

−

m

initial

=

250

l

g

−

120

l

g

=

130

l

g

−−−−−

The initial volume of water in the graduated cylinder was

30

mL

, and the volume after the rock was added read

75

mL

, so the rock's volume is

V

rock

=

V

final

−

V

initial

=

75

l

mL

−

30

l

mL

=

45

l

mL

−−−−−−

The equation for the density of the rock is

density

=

mass

volume

And so we have

density

=

130

l

g

45

l

mL

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2.9

l

g/mL

=

2.9

l

g/cm

3

∣

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−−

Explanation:

Sorry i had to look it up

Please mark brainliest:)

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

yup its correct its: c) b b