Two identical point charges of +Q are separated by a distance of 10cm I) calculate the work done per unit charge to bring up another charge from far away along a perpendicular bisector of the line joining two charges to the point Midway between the charges.
ii)if one of the charges in part(a)is charged from +Q to -Q, calculate the work done per unit charge to bring up a charge to the same position as above

i wanna say it’s between b and d, leaning more towards b.

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.

your answer is, orbit around the nucleus

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s