A student fires a cannonball vertically upwards. The cannonball returns to the ground after a 4.60s flight. Determine all unknowns and answer the following
questions. Neglect drag and the initial height and horizontal motion of the
cannonball. Use regular metric units (ie. meters).
How long did the cannonball rise?
unit
What was the cannonball's initial speed?
unit
What was the cannonball's maximum height?
unit
V

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

Put the value into the formula

We need to calculate the distance

Using formula of distance

Put the value into the formula

We need to calculate the maximum height

Using equation of motion

Put the value into the formula

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

hope this : )

explanation:

be subject to a force andchange its motion