In a certain semiconducting material the charge carriers each have a charge of 1.6 x 10-19 C. How many are entering the semiconductor per second when the current is 2.0 nA?

1124923453 electrons

Explanation:

The formula for charge in coulomb ,C =Current in amperes, A * Time in seconds, s

Given in question ;

Charge = 1.6 * 10⁻¹⁹ C

Current = 2.0 nA = 2*e⁻⁹ A

Calculate time in seconds as

1.6 * 10⁻¹⁹ = 2*e⁻⁹ * t

1.6 * 10⁻¹⁹ /2*e⁻⁹  = t

6.48e⁻¹⁶  s = t

So using t=6.48e⁻¹⁶  s and current =2*e⁻⁹ A , the charge will be;

C = 2*e⁻⁹  * 6.48e⁻¹⁶  =1.799e⁻¹⁰ C

But 1 coulomb = 6.25 x 10¹⁸ electrons

so 1.799e⁻¹⁰ C = ?{ 6.25 x 10¹⁸} *{1.799e⁻¹⁰} =  1124923453.06 electrons

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle