A train starting from a distance of velocity of 90 km. h -1 in 10 minutes assuming that the acceleration is uniform find the acceleration and the distance travelled by the train for attending the velocity

To make this problem solvable and you can get the help you need, I'll complete and arrange some data.

Acceleration: , Distance=7,500 m

Explanation:

Uniform Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly over time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

The distance traveled by the object is given by:

Using the equation [1] we can solve for a:

The problem will be rewritten as follows:

A train starting from rest reaches a velocity of 90 km/h in 10 minutes. Assuming that the acceleration is uniform, find the acceleration and the distance traveled by the train for attending the velocity.

Let's take the relevant data:

vo=0

vf=90 Km/h*1000/3600 = 25 m/s

t = 10 minutes = 10*60 = 600  seconds

Now compute the acceleration by using [3]:

Finally, compute the distance:

Note: We used the value of the acceleration with more precision than shown.

Acceleration: , Distance=7,500 m

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.