A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds. What is the magnitude of the total change in the external magnetic flux enclosed by the coil

Δϕ = -2.89 x 10^-4 Wb

Explanation:

Given that A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds. What is the magnitude of the total change in the external magnetic flux enclosed by the coil

Let ΔB = Change in magnetic field

A = cross sectional area = 8.5 cm^2

t = time = 12ms

Flux change = Δϕ = (ΔB*A) / t

Δϕ =  [(0.02 - 0.06)x(8.5 x 10^-2)^2 ] / 0.012

Δϕ = (-0.04 x 7.225^-3) / 0.012

Δϕ = -2.89 x 10^-4 Wb

Therefore, the magnitude of the total change in the external magnetic flux enclosed by the coil is -2.89 x 10^-4 Wb

i believe the answer would be:

d. violin, clarinet, french horn, and tuba

higher potential

explanation:

because it is in a high speed so it must move into a of high potential