A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of 208\,\dfrac{\text m}{\text s}208 s m 208, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction from a height of 94\,\text m94m94, start text, m, end text. We can ignore air resistance.

a. 42.92 m/s b 4.4 s c. 915.2 m

Explanation:

Here is the complete question

A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of   208 m/s, from a height of 94 m. We can ignore air resistance.

What is the vertical velocity of the magma when it hits the ground?

Solution

a. Using v² = u² - 2gy since it is motion under gravity, where u = initial vertical velocity = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and y =  height = 94 m.

Substituting these values into the equation, we have

v² = u² - 2gy

v² = 0² - 2 × (-9.8 m/s²) × 94 m

v² = 1842.4 m²/s²

v = √1842.4 m²/s²

v = 42.92 m/s

b. We also find the time it takes to drop from the height of 94 m from

y = ut - 1/2gt² , u = 0

So, t = √(2y/g)

= √(2 × 94 m ÷ 9.8 m/s²)

= √19.184 s²

= 4.4 s

c. The horizontal distance the chunk of hot magma covers is thus x = Vt where v = horizontal velocity = 208 m/s

x = 208 m/s × 4.4 s = 915.2 m

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

radial fractures in a piece of glass look most like which of the following?

a. spokes of a wheel

b. a circle

c. a zig zag

d. none of the above

the correct answer is a. spokes of a wheel

hope this (: