An object is traveling with a velocity of 3.05 m/s. The object then accelerates at 2.82 m/s-over a displacement of 18.4 m. What is its final velocity?

Final velocity (v) = 5.148 m/s (Approx)

Explanation:

Given:

Initial velocity (u) = 3.05 m/s

Acceleration (a) = 2.82 m/s²

Displacement (s) = 18.4 m

Find:

Final velocity (v)

Computation:

v² = u² + 2as

v² = (3.05)² + 2(2.82)(3.05)

v² = 9.3025 + 17.202

v² = 26.5045

v = 5.148 m/s (Approx)

f=gm1m2/d^2 it d

f is force g is gravitaiton constant, m1 is mass of first object, m2 is mass of second object. d is distance between two object

b.

explanation:

10.0