If you drop a rock from a height of 13 m, it accelerates at 9.8 m/s2 and strikes the ground 1.62882 s later. If you drop the same rock from half that height, what will be its acceleration?

You had me worried there for a second.  I thought you were going to ask how much the time changes, or how much the speed changes as it hits the ground, and I was gonna skip this question and go to bed.

But the acceleration won't change.  That's always 9.8 m/s².  That's the acceleration of gravity on Earth. It doesn't depend on what you drop, or what its mass is, or how heavy it is, or what color it is, or how high you drop it from. The only way you can change it is to drop the rock through air or water, or on a different planet.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.