It was once recorded that a Jaguar left skid marks that were 320 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -2.2 m/s2 , determine the speed of the Jaguar before it began to skid.

The speed of the Jaguar before it began to skid : 32.532 m/s

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration  

An equation of uniformly accelerated motion  

vt = vo + at  

vt² = vo² + 2a (x-xo)  

x = distance on t  

vo / vi = initial speed  

vt / vf = speed on t / final speed  

a = acceleration  

answer: (431,2)

step-by-step explanation: