You push a 23 kg chair horizontal along the floor and it accelerates at 0.53 m/s2. If the coefficient of kinetic friction between the chair and the floor is 0.35, calculate the magnitude of your force.

F = 91.08 N

Explanation:

It is given that,

Mass of a chair, m = 23 kg

Acceleration of the chair, a = 0.53 m/s²

The coefficient of kinetic friction between the chair and the floor is 0.35

We need to find the magnitude of the applied force. Let f is the frictional force and F is the applied force. We can use the equation of motion as follows :

F-f=ma

Also,

So,

So, the magnitude of the applied force is 91.08 N.

he kicked it 10 feet straight up into the air? i think this works.