1. A racing car reaches a speed of 40.0 m/s. At this instant, it begins a uniform negative acceleration, using a parachute as a braking system, and comes to rest in 5.00 s.
(a) Determine the acceleration of the car.
(b) How far does the car travel after acceleration starts?

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

im guessing the west of station b

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j