. A car is traveling in a straight line path at a maximum speed of 7.00 m/s. The driver of the vehicle applies the brakes bringing the car to a stop after traveling 10.0 m. What is the magnitude of the car's acceleration to the nearest hundredths place?

Acceleration = -2.45 m/s²

Explanation:

Given:

Initial speed u = 7 m/s

Final speed v = 0 m/s

Distance s  = 10 m

Find:

Acceleration

Computation:

v² = u² + 2as

0² = 7² + 2a(10)

0 = 49 + 20 a

-49 / 20 = a

Acceleration = -2.45 m/s²

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explanation:

the answer is a. at the equator