Physics, 26.10.2020 09:00 sandyrose935

Calculate the ratio of the mechanical energy at B and mechanical energy at a (eb, ea) and (ec, ea). What do these ratios tell you about the conservation of energy? A) is the mechanical conserved between a and b? explain

B) is the mechanical energy conserved between b and c ?explain

Calculate the ratio of the mechanical energy at B and mechanical energy at a (eb,ea) and (ec,ea). W

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Answer from: wickedskatboarder

(a) The ratio of the mechanical energy at B and mechanical energy at A is 0.36.

(b) The ratio of the mechanical energy at C and mechanical energy at A is 0.

(d) mechanical energy is not conserved between b and c.

The given parameters;

mechanical energy at A, $E_a = 2,940 \ J$ mechanical energy at B, $E_b =1,058.3 \ J$ mechanical energy at C, E_c = 0

The ratio of the mechanical energy at B and mechanical energy at A;

$ratio = \frac{E_b}{E_a} = \frac{1058.3}{2940} = 0.36$

The ratio of the mechanical energy at C and mechanical energy at A;

$ratio = \frac{E_c}{E_a} = \frac{0}{2940} = 0$

The change mechanical energy between A and B from the given position;

$\Delta E = mg(h_b - h_a) - \frac{1}{2}m(v_b^2 - v_a^2)\\\\ \Delta E = 50\times 9.8(2-6) \ - \ \frac{1}{2} \times 50(8.85^2 - 0)\\\\\Delta E =- 1960 + 1960\\\\\Delta E = 0 \ J$

Thus, we can conclude that mechanical energy is conserved between a and b.

The change mechanical energy between A and B from the given position;

$\Delta E = mg(h_c - h_b) - \frac{1}{2}m(v_c^2 - v_b^2)\\\\ \Delta E = 50\times 9.8(0-2) \ - \ \frac{1}{2} \times 50(0^2 - 8.85^2)\\\\\Delta E = -980 + 1960 \\\\\Delta E = 980 \ J$

Thus, we can conclude that mechanical energy is not conserved between b and c.

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Answer from: arivalen

Yes at A the mechanical energy is conserved.

Yes at B the part of mechanical energy is conserved potential energy and kinetic energy and some is lost as frictional force.

Explanation:

Ratio = Eb/ Ea= 1058.3 J/2940 J= 0.3599

Ratio = Ec/ Eb= 0J/ 1058.3 J= 0

At point A the skater is at rest or it is the starting point and the whole energy is due to the position of the skater i.e= mgh = 50 *9.8*6= 2940 J

Since there's no movement there is no Kinetic energy = 0 J

Yes at A the mechanical energy is conserved.

At point B the skater has traveled for some of the distance . It has potential energy and kinetic energy.

Yes at B the part of mechanical energy is conserved as potential energy and kinetic energy.

The total Mechanical energy = 1058.3 J

At point B Total Mechanical energy = PE+ KE

1058.3J = 980 J + 78.3 J

1058.3 J = mgh + 1/2mv²

= 50*2*9.8 + 1/2 *50*(8.85)²

= 980 J + 78.3 J

As the total energy of the system must remain the same some of the mechanical energy is lost as frictional force at point B .

2940 J-1058.3 J= 1881.7

At Point C the skater has arrived at the end point and the height , speed, PE, KE and ME all are zero.

Answer from: Quest

4. 50x10= 500m/s 5. 52m/s
First to answer will be the brainliest answer both questions 4 and 5 and don't answer if you don't k

Answer from: Quest

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat

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