Consider an ionic compound, MXMX , composed of generic metal MM and generic, gaseous halogen XX . The enthalpy of formation of MXMX is ΔH∘f=−421ΔHf∘=−421 kJ/mol. The enthalpy of sublimation of MM is ΔHsub=155ΔHsub=155 kJ/mol. The ionization energy of MM is IE=401IE=401 kJ/mol. The electron affinity of XX is ΔHEA=−321ΔHEA=−321 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=239BE=239 kJ/mol. Determine the lattice energy of MXMX .

- 775.5 kJ/mol

Explanation:

Given that:

The enthalpy of formation of MX is = - 421 kJ/mol

The enthalpy of sublimation of MM is =  155  kJ/mol

The ionization energy of MM is  = 401 kJ/mol

The electron affinity of XX is   = -321 kJ/mol

The bond energy of X2 is BE = 239 J/mol

The process for each above component is shown below:

Thus, the overall reaction is:

The overall energy is:

- 421 kJ/mol = U + 155 kJ/mol + 401 kJ/mol + 119.5 kJ/mol + (-321 kJ/mol)

- 421 kJ/mol = U + 354.5 kJ/mol

- U = 421 kJ/mol + 354.5 kJ/mol

- U = 421 kJ/mol + 354.5 kJ/mol

- U = 775.5 kJ/mol

U = - 775.5 kJ/mol

Thus, the lattice energy of MX (U) = - 775.5 kJ/mol

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

the ima (higher than 1m) will be greater than the ima with the height of 1m.