The equation you found in Part D may be factored to give(E2−E1)(E2+E1)=p22c2−p21c2.Cons ider the term E2+E1. Since we are looking at the "everyday" limit of relativity, where speed is far lower than the speed of light, the kinetic energy will be negligible compared to the rest energy. Using this approximation, find the value of E2+

Complete Question

The equation you found in Part D may be factored to give(E2−E1)(E2+E1)=p22c2−p21c2.Consider the term E2+E1. Since we are looking at the "everyday" limit of relativity, where speed is far lower than the speed of light, the kinetic energy will be negligible compared to the rest energy. Using this approximation, find the value of E2+E1

The  value  is  

Explanation:

Generally in the question we are given this equation  

and the objective is to obtain  the value of   in terms of  m and  c

Generally kinetic energy is mathematically represented as

=>  

recall that momentum is mathematically represented as

Hence

=>  

Hence       and  

So

=>  

So from the given equation

=>  

=>  

=>        

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length