A crane is lifting a 500-kg object at a constant speed of 0.5 m/s. What is the power output of the crane

The power output is 2450 W

Explanation:

Give;

mass of the object, m = 500 kg

velocity of the object, v = 0.5 m/s

The power output is given  by the following equation;

P = F x V

Where;

P is the output power

F is the applied force

P = (mg) x v

P = ( 500 x 9.8) x 0.5

P = 2450 W

Therefore, the  power output is 2450 W

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation