A 730-N Marine in basic training climbs a 11.5-m vertical rope at a constant speed in 8.25 s. What is his power output

1017.58Watts

Explanation:

A 730-N Marine in basic training climbs a 11.5-m vertical rope at a constant speed in 8.25 s. What is his power output

From the formula to calculate power; Power=workdone/time which can be expressed below;

P = W/t

But Workdone= Force× distance

Then power= (Force× distance)/time

Which can be expressed below;

Power = F×d/t

P = power output= ?

Force= 730-N

displacement= 11.5-m

time=8.25 s.

Let us calculate our workdone first as

Workdone = (730 N)(11.5 m)= 8395Nm

Since we know our workdone now, we calculate the Power as;

Power=workdone/time

Power= 8395Nm/8.25 s.

= 1017.58Nm/s

= 1017.58Joules/seconds

1017.58Watts

Therefore, his power output is

1017.58Watts.

NOTE:We can also convert to HORSE POWER , 0.00134Hp= 1watt

Then 1017.58Watts= ( 0.00134Hp× 1017.58Watt)

= 1.36horse power.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: