Please help!! What is the impulse given to a tennis ball hit with an average force of 522 N if the racket is in contact with the ball for 0.22 seconds?

114.84

Explanation:

Impulse= F.ΔT

where F is the average force applied and ΔT is the change in time period

so,

Impusle= (522)x(0.22)

Impulse=114.84N-s

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j