A box slides off a perfectly horizontal table with an initial speed of 2 m/s. The table is 1.5m off the ground. Vx = 2.0 m/s
1.5 m
What is the speed of the box just as it hits the ground?

The speed of the box just as it hits the ground is 5.8 m/s

Explanation:

Given;

initial velocity of the box, u = 2 m/s

height of the table, h = 1.5 m

The speed of the box, just before it hits the ground is given by;

v² = u² + 2gh

v² = (2)² + 2 x 9.8 x 1.5

v² = 4 + 29.4

v² = 33.4

v = √33.4

v = 5.8 m/s

Therefore, the speed of the box just as it hits the ground is 5.8 m/s

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.