Consider two current-carrying circular loops. Both are made from one strand of wire and both carry the same current, but one has twice the radius of the other. If the magnetic field strength at the center of the smaller loop is B, what is the magnetic field strength at the center of the larger loop

Explanation:

The magnetic field at the center of a current-carrying circular loop is given by :

Where, I is current and r is radius of loop

We have, two current-carrying circular loops. Both are made from one strand of wire and both carry the same current, but one has twice the radius of the other.

For smaller loop, the magnetic field is B (with radius r)

For larger loop, let the magnetic field be B' (with radius r', r'=2r). So,

Hence, the magnetic field strength at the center of the larger loop is half of the magnetic field strength at the center of the smaller loop.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

where is the photo and the answer choices?