Acatapult launches a boulder with an upward velocity of 92 m/s. the height of the boulder, h, in meters after t seconds is given by the function h=-5t^2+92t+16. how long does it take to reach maximum height? what is the boulders maximum height?

Explanation:

It is given that,

Upward velocity of a boulder, v = 92 m/s

The height of the boulder, h, in meters after t seconds is given by the function as :

............(1)

We have to find the time taken by boulder to reach maximum height. For this, we have to differentiate equation (1) w.r.t. t and putting it equal to 0. So,

t = 9.2 s

Putting the value of t = 9.2 s in equation (1). So,

h = 439.2 m

So, the time taken by it to reach maximum height is 9.2 s and the maximum height is 439.2 m. Hence, this is the required solution.

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down