How far will a 600kg boat travel in 12 s if there is a constant 900N force on it and it starts from rest?

d = 108 m

Explanation:

Given that,

Initial speed, u = 0

Mass of the boat, m = 600 kg

Time, t = 12 s

Force on boat, F = 900 N

Firstly, we can find the acceleration of the boat using formula, F = ma

Let it will travel d distance. Using second equation of motion to find it as follows :

So, the boat will travel 108 m.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

i don't know that i agree with that but what's the question ?