A vertical rope is attached to an object that has a mass of 40.0 kg and is at rest. The tension in the rope needed to give the object an upward speed of 3.50 m/s
in 0.700 s is

239.2 N

Explanation:

Given that a vertical rope is attached to an object that has a mass of 40.0 kg and is at rest.The tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is

The tension in the rope and the weight of the mass will be acting in an opposite direction.

T - mg = ma (1)

Where acceleration a = Velocity/ time

a = 3.5 / 0.7

a = 5 m/s^2

Substitutes acceleration a into the equation 1 above.

T - 40 × 9.8 = 40 × 5

T - 39.2 = 200

T = 200 + 39.2

T = 239.2N

Therefore, the tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is 239.2N

i don't know that i agree with that but what's the question ?

small = small current large mag large current